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@Master-Killer
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Hello.
Pretty sure that the 'with' syntax for inferable parameter is deprecated and has been replaced by the 'given' syntax.

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@Master-Killer
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At the very end, there is also this line:
ConstrApps ::= ConstrApp {‘with’ ConstrApp}

I think this 'with' should also be replaced by 'given', but I am not sure at all.

@odersky
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odersky commented Feb 23, 2019

Thanks for the fixes!

ConstrApps ::= ConstrApp {‘with’ ConstrApp}

No, here the with means mixin, so no given.

@odersky odersky merged commit 40a7d10 into scala:master Feb 23, 2019
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3 participants