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Added another solution for "cats_in_hats" with using nested cycles #84

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Added another solution for "cats_in_hats" with using nested cycles #84

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12 changes: 12 additions & 0 deletions ch09-lists-tuples-and-dictionaries/9d-challenge-cats-with-hats.py
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Original file line number Diff line number Diff line change
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# 9.9 - Challenge: Cats With Hats
# Alternative solution to challenge(nested loops)

for i in range(1,101):
# Counting number of actions with hat
count = 1
for j in range(1, i):
if i % j == 0:
count += 1
# Determine what action was last
if count % 2 == 1:
print(f"Cat {i} has a hat.")