scaled_float still has precision problem

[kyreddie]

Reproduced on Elasticsearch version 6.3.2 in Elastic Cloud

Looks like this was addressed in [https://github.com//pull/27207] but problem still exists.

Steps to reproduce:

PUT testindex{
"settings":{
"number_of_shards":1
},
"mappings":{
"type1":{
"properties":{
"field1":{
"type":"scaled_float",
"scaling_factor":100
}
}
}
}
}

PUT /testindex/type1/1?pretty{
"field1":79.99
}

GET testindex/_search{
"query":{
"bool":{
"must":[
{
"range":{
"field1":{
"gte":0,
"lte":79.99
}
}
}
]
}
}
}

Query results in 0 hits. Looks like the query is being resolved to field1:[0 TO 7998], which is incorrect. I would expect to return document

Looking at the code, could we cast dValue to a float?? hi = Math.round(Math.floor((float)dValue));

[elasticmachine]

Pinging @elastic/es-search-aggs

[kyreddie]

cc: @original-brownbear

[original-brownbear]

I'm not sure this is a bug actually. The scaling factor is just too small as far as I understand the definition of the scaling factor.
If you scale by 100 then you will still effectively round the last digit here since we have 4 digits here (e.g. on my box 79.99d * 100 = 7998.9999999... => casts to 7998 since we're always rounding down for lte comparisons).

@jpountz probably knows this better than me though :) so ping :)

[sergiosalvatore]

Hmm -- seems like there's definitely some confusion then. From the Elasticsearch documentation:

For instance, a price field could be stored in a scaled_float with a scaling_factor of 100. All APIs would work as if the field was stored as a double, but under the hood Elasticsearch would be working with the number of cents, price*100, which is an integer.

In terms of "round tripping," my understanding according to the documentation referenced above is that internally, when a document with the value 79.99 is stored in a scaled_float field, it's stored as 7999 in the index. When I request that stored document, the value is indeed returned as 79.99 scaled appropriately. It seems that it should follow the same process for filters as it is when storing/retrieving the value.

[eskibars]

At minimum, we need to make a better declaration on how this works and limitations. The documentation currently reads:

Values will be multiplied by this factor at index time and rounded to the closest long value.

For an input value of 79.99 and a scaling factor of 100, I think it's reasonable for a user to expect 79.99*100=7999. I don't think the user reasonably expects that 79.99 * 10 = 7998.9999... unless you're familiar with the internals. The docs either need to imply round down logic or the feature needs to give you the closest value really / we need to define how a user should understand it to work.

[colings86]

We discussed this in FixItFriday and the outcome is that we feel this is a bug as users do not know (and should not reasonably know) the ins and outs of binary floating point representations. The problem here seems to be centred around us doing the wrong thing to resolve the value of the lte field. We should fix this so that instead of just doing 79.99 * 100 here we do Math.floor(79.99 * 100 + 0.5) and make the bound lt instead of lte so we search from 0 to less than "the next representable value higher than 79.99)

[jpountz]

This approach would still have similar problems, they would just occur on the half point between representable values rather than on representable values themselves? Alternatively maybe we could use big decimals to delay rounding to after the multiplication (which is where the fact that doubles do not represent numbers accurately gets amplified) by replacing Double.parseDouble(boundary) * scalingFactor with something like new BigDecimal(boundary).multiply(BigDecimal.valueOf(scalingFactor)).doubleValue()?

[original-brownbear]

@jpountz

I don't think using BigDecimal here will help, if I try it in the debugger then:

new BigDecimal(parse(upperTerm)).multiply(BigDecimal.valueOf(scalingFactor)).doubleValue() == parse(upperTerm) * scalingFactor

returns true.

I think this is a principal problem with double and the equals-type comparisons:

• We can't just use arithmetic rounding here to resolve the fact that 79.99 will be slightly less than than internally because that would mess up the behaviour for things like < 17.55 with a small scaling factor because it could round to 18.

=> we can't really fix the feature to get the desired behaviour here as far as I can see.

=> We should probably fix the docs?
... the other option I see would be to change the storage behaviour scaled_float slightly and simply use another digit internally. That way we'd get the expected behaviour because we wouldn't have a rounding error on the last digit at the cost of storing an extra digit wouldn't we?

[jpountz]

@original-brownbear Try new BigDecimal(Double.toString(parse(upperTerm))).multiply(BigDecimal.valueOf(scalingFactor)).doubleValue(). The BigDecimal needs to be constructed out of the string representation of the number, otherwise it inherits the accuracy loss of the double representation which causes this issue.

[original-brownbear]

@jpountz huh you're right! That works :)

jshell> new BigDecimal(Double.toString(79.99)).multiply(BigDecimal.valueOf(100)).doubleValue()
$6 ==> 7999.0

[DaveCTurner]

I think I suggested the Math.floor(79.99 * 100 + 0.5) idea to fix this query for representable values but it's right that it doesn't work for some value that's around half-way between two representable values. BigDecimal seems like a good answer to dealing with unrepresentable values correctly but it seems like any double in the process is going to lead to difficulty because of facts like 79.999999999999993 == 80.0:

DELETE /i

PUT /i
{
  "mappings": {
    "_doc": {
      "properties": {
        "f": {
          "scaling_factor": 100,
          "type": "scaled_float"
        }
      }
    }
  },
  "settings": {
    "number_of_shards": 1,
    "number_of_replicas": 0
  }
}

POST /i/_doc/_bulk?refresh
{"index":{}}
{"f":79.98}
{"index":{}}
{"f":79.99}
{"index":{}}
{"f":80.00}

GET /i/_search
{
  "query": {
    "range": {
      "f": {
        "lte": 79.999999999999993
      }
    }
  }
}

I think this should not yield all 3 docs, but it does.

[jpountz]

Yeah I was going to comment with an example like that after reading that "users do not know (and should not reasonably know) the ins and outs of binary floating point representations". I think this is a good example why we can't (reasonably) hide this problem entirely from our users.

I'm not too worried about this issue since users will only face it if they represent numbers on client-side with something that is more accurate than doubles, which is uncommon.

Also for the record, scaled_float is not the only type affected by this issue, all our numeric types are.