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Added Set Mismatch easy problem. #5

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Added Set Mismatch easy problem. #5

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12 changes: 12 additions & 0 deletions Sets/Set Mismatch
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Original file line number Diff line number Diff line change
@@ -0,0 +1,12 @@
The idea is using array indexing, that is putting each nums[i] into the position with index nums[i] - 1. Then, the array becomes [1,2,3,4,5...,n]. So we can find the duplicate number when nums[i] != i+1.

```
vector<int> findErrorNums(vector<int>& nums) {
for(int i = 0; i<nums.size(); i++){
while(nums[i] != nums[nums[i] - 1])swap(nums[i], nums[nums[i] - 1]);
}
for(int i = 0; i<nums.size() ; i++){
if(nums[i] != i + 1)return {nums[i], i + 1};
}
}
````