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Update 1_questions_and_solutions.sql #18

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27 changes: 11 additions & 16 deletions SQL_exercise_01/1_questions_and_solutions.sql
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Original file line number Diff line number Diff line change
Expand Up @@ -90,22 +90,17 @@ ORDER BY price ASC


-- 1.16 Select the name of each manufacturer along with the name and price of its most expensive product.
select max_price_mapping.name as manu_name, max_price_mapping.price, products_with_manu_name.name as product_name
from
(SELECT Manufacturers.Name, MAX(Price) price
FROM Products, Manufacturers
WHERE Manufacturer = Manufacturers.Code
GROUP BY Manufacturers.Name)
as max_price_mapping
left join
(select products.*, manufacturers.name manu_name
from products join manufacturers
on (products.manufacturer = manufacturers.code))
as products_with_manu_name
on
(max_price_mapping.name = products_with_manu_name.manu_name
and
max_price_mapping.price = products_with_manu_name.price);
SELECT Products.Name as "Products Name",
Products.Price as "Price",
Manufacturers.Name as "Manufacture Company"
from Products,Manufacturers
where Products.Manufacturer = Manufacturers.Code
and Products.Price =
(
select max(Products.Price)
from Products
where Products.Manufacturer = Manufacturers.Code
);



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