check whether integer is even or odd using bit manupulation

bit_manipulation/even_or_not.py

@@ -0,0 +1,40 @@
+def is_even(number: int) -> bool:
+    """
+    return true if the input integer is even
+    Explanation: Lets take a look at the following deicmal to binary conversions
+    2 => 10
+    14 => 1110
+    100 => 1100100
+    3 => 11
+    13 => 1101
+    101 => 1100101
+    from the above examples we can observe that
+    for all the odd integers there is always 1 set bit at the end
+    also, 1 in binary can be represented as 001, 00001, or 0000001
+    so for any odd integer n => n&1 is always equlas 1 else the integer is even
+
+    >>> is_even(1)
+    False
+    >>> is_even(4)
+    True
+    >>> is_even(9)
+    False
+    >>> is_even(15)
+    False
+    >>> is_even(40)
+    True
+    >>> is_even(100)
+    True
+    >>> is_even(101)
+    False
+    """
+    if number & 1 == 0:
+        return True
+    else:
+        return False
+
+
+if __name__ == "__main__":
+    import doctest
+
+    doctest.testmod()