Add solution and test-cases for problem 3349

leetcode/3301-3400/3349.Adjacent-Increasing-Subarrays-Detection-I/README.md

@@ -1,28 +1,34 @@
 # [3349.Adjacent Increasing Subarrays Detection I][title]
 
-> [!WARNING|style:flat]
-> This question is temporarily unanswered if you have good ideas. Welcome to [Create Pull Request PR](https://github.com/kylesliu/awesome-golang-algorithm)
-
 ## Description
+Given an array `nums` of `n` integers and an integer `k`, determine whether there exist **two adjacent** subarrays of length `k` such that both subarrays are **strictly increasing**. Specifically, check if there are two subarrays starting at indices `a` and `b` (`a < b`), where:
+
+- Both subarrays `nums[a..a + k - 1]` and `nums[b..b + k - 1]` are **strictly increasing*8.
+- The subarrays must be **adjacent**, meaning `b = a + k`.
+
+Return `true` if it is possible to find **two** such subarrays, and `false` otherwise.
 
 **Example 1:**
 
 ```
-Input: a = "11", b = "1"
-Output: "100"
-```
+Input: nums = [2,5,7,8,9,2,3,4,3,1], k = 3
 
-## 题意
-> ...
+Output: true
 
-## 题解
+Explanation:
 
-### 思路1
-> ...
-Adjacent Increasing Subarrays Detection I
-```go
+The subarray starting at index 2 is [7, 8, 9], which is strictly increasing.
+The subarray starting at index 5 is [2, 3, 4], which is also strictly increasing.
+These two subarrays are adjacent, so the result is true.
 ```
 
+**Example 2:**
+
+```
+Input: nums = [1,2,3,4,4,4,4,5,6,7], k = 5
+
+Output: false
+```
 
 ## 结语
 

leetcode/3301-3400/3349.Adjacent-Increasing-Subarrays-Detection-I/Solution.go

@@ -1,5 +1,27 @@
 package Solution
 
-func Solution(x bool) bool {
-	return x
+func Solution(nums []int, k int) bool {
+	indies := map[int]struct{}{}
+	start, end := 0, 0
+	curLen := 0
+	pre := -1001
+	for ; end < len(nums); end++ {
+		if nums[end] <= pre {
+			start, curLen = end, 1
+		} else {
+			curLen++
+		}
+		pre = nums[end]
+		if curLen == k {
+			indies[start] = struct{}{}
+			start++
+			curLen--
+		}
+	}
+	for index := range indies {
+		if _, ok := indies[index+k]; ok {
+			return true
+		}
+	}
+	return false
 }

leetcode/3301-3400/3349.Adjacent-Increasing-Subarrays-Detection-I/Solution_test.go

@@ -10,30 +10,30 @@ func TestSolution(t *testing.T) {
 	//	测试用例
 	cases := []struct {
 		name   string
-		inputs bool
+		inputs []int
+		k      int
 		expect bool
 	}{
-		{"TestCase", true, true},
-		{"TestCase", true, true},
-		{"TestCase", false, false},
+		{"TestCase1", []int{2, 5, 7, 8, 9, 2, 3, 4, 3, 1}, 3, true},
+		{"TestCase2", []int{1, 2, 3, 4, 4, 4, 4, 5, 6, 7}, 5, false},
 	}
 
 	//	开始测试
 	for i, c := range cases {
 		t.Run(c.name+" "+strconv.Itoa(i), func(t *testing.T) {
-			got := Solution(c.inputs)
+			got := Solution(c.inputs, c.k)
 			if !reflect.DeepEqual(got, c.expect) {
-				t.Fatalf("expected: %v, but got: %v, with inputs: %v",
-					c.expect, got, c.inputs)
+				t.Fatalf("expected: %v, but got: %v, with inputs: %v %v",
+					c.expect, got, c.inputs, c.k)
 			}
 		})
 	}
 }
 
-//	压力测试
+// 压力测试
 func BenchmarkSolution(b *testing.B) {
 }
 
-//	使用案列
+// 使用案列
 func ExampleSolution() {
 }