diff --git a/index.ipynb b/index.ipynb index cd283629c8d..ad06e8f2ac9 100644 --- a/index.ipynb +++ b/index.ipynb @@ -1 +1,3153 @@ -{"cells": [{"cell_type": "markdown", "metadata": {}, "source": ["# Python For loops Lab"]}, {"cell_type": "markdown", "metadata": {}, "source": ["### Learning Objectives"]}, {"cell_type": "markdown", "metadata": {}, "source": ["* Understand how for loops can help us reduce repetition\n", "* Understand the syntax of for loops "]}, {"cell_type": "markdown", "metadata": {}, "source": ["### Picking up where we last left off"]}, {"cell_type": "markdown", "metadata": {}, "source": ["In the last lesson, we worked with some of our travel data. Let's retrieve a list with our travel information again from excel. First, we read the information from excel as a list of dictionaries, with each dictionary representing a location. And we assign this list to the variable `cities`."]}, {"cell_type": "code", "execution_count": null, "metadata": {}, "outputs": [], "source": ["import pandas\n", "file_name = './cities.xlsx'\n", "travel_df = pandas.read_excel(file_name)\n", "cities = travel_df.to_dict('records')"]}, {"cell_type": "markdown", "metadata": {}, "source": ["Next, we retrieve the first three city names, stored as the `'City'` attribute of each dictionary, and `'Population'` of each of the cities. Then we plot the names as our `x_values` and the populations as our `y_values`."]}, {"cell_type": "code", "execution_count": null, "metadata": {}, "outputs": [], "source": ["import plotly\n", "\n", "plotly.offline.init_notebook_mode(connected=True)\n", "\n", "x_values = [cities[0]['City'], cities[1]['City'], cities[2]['City']]\n", "y_values = [cities[0]['Population'], cities[1]['Population'], cities[2]['Population']]\n", "trace_first_three_pops = {'x': x_values, 'y': y_values, 'type': 'bar'}\n", "plotly.offline.iplot([trace_first_three_pops])"]}, {"cell_type": "markdown", "metadata": {}, "source": ["Of course, as you may have spotted, there is a good amount of repetition in displaying this data. Just take a look at how we retrieved the data for our `x_values` and `y_values`. "]}, {"cell_type": "code", "execution_count": null, "metadata": {}, "outputs": [], "source": ["x_values = [cities[0]['City'], cities[1]['City'], cities[2]['City']]\n", "y_values = [cities[0]['Population'], cities[1]['Population'], cities[2]['Population']]"]}, {"cell_type": "markdown", "metadata": {}, "source": ["So in this lesson, we will use our `for` loop to display information about our travel locations with less repetition."]}, {"cell_type": "markdown", "metadata": {}, "source": ["### Working with the For Loop"]}, {"cell_type": "markdown", "metadata": {}, "source": ["Our `cities` list contains information about the top 12 cities by population. For our upcoming iteration tasks, it will be useful to have a list of the numbers 0 through 11. Use what we know about `len` and `range`to generate a list of numbers 0 through 11. Assign this to a variable called `city_indices`."]}, {"cell_type": "code", "execution_count": null, "metadata": {}, "outputs": [], "source": ["city_indices = None\n", "city_indices # [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11]"]}, {"cell_type": "markdown", "metadata": {}, "source": ["Now we want to create labels for each of the cities. We'll provide a list of the `city_names` for you. "]}, {"cell_type": "code", "execution_count": null, "metadata": {}, "outputs": [], "source": ["city_names = ['Buenos Aires',\n", " 'Toronto',\n", " 'Marakesh',\n", " 'Albuquerque',\n", " 'Los Cabos',\n", " 'Greenville',\n", " 'Archipelago Sea',\n", " 'Pyeongchang',\n", " 'Walla Walla Valley',\n", " 'Salina Island',\n", " 'Solta',\n", " 'Iguazu Falls']"]}, {"cell_type": "markdown", "metadata": {}, "source": ["Your task is to assign the variable `names_and_ranks` to a list, with each element equal to the city name and it's corresponding rank. For example, the first element would be, `\"1. Buenos Aires\"` and the second would be `\"2. Toronto\"`. Use a `for` loop and the lists `city_indices` and `city_names` to accomplish this. We'll need to perform some nifty string interpolation to format our strings properly. Check out [f-string interpolation](https://www.programiz.com/python-programming/string-interpolation#f) to see how we can pass values into a string. Remember that list indices start at zero, but we want our `names_and_ranks` list to start at one!"]}, {"cell_type": "code", "execution_count": null, "metadata": {}, "outputs": [], "source": ["names_and_ranks = [] \n", "# write a for loop that adds the properly formatted string to the names_and_ranks list"]}, {"cell_type": "code", "execution_count": null, "metadata": {}, "outputs": [], "source": ["names_and_ranks[0] # '1. Buenos Aires'\n", "names_and_ranks[1] # '2. Toronto'\n", "names_and_ranks[-1] # '12. Iguazu Falls'"]}, {"cell_type": "markdown", "metadata": {}, "source": ["Ok, now let's create a new variable called `city_populations`. Use a `for` loop to iterate through `cities` and have `city_populations` equal to each of the populations."]}, {"cell_type": "code", "execution_count": null, "metadata": {}, "outputs": [], "source": ["city_populations = []"]}, {"cell_type": "code", "execution_count": null, "metadata": {}, "outputs": [], "source": ["city_populations[0] # 2891\n", "city_populations[1] # 2732\n", "city_populations[-1] # 0"]}, {"cell_type": "markdown", "metadata": {}, "source": ["Great! Now we can begin to plot this data. First, let's create a trace of our populations and set it to the variable `trace_populations`."]}, {"cell_type": "code", "execution_count": null, "metadata": {}, "outputs": [], "source": ["trace_populations = {'x': names_and_ranks, \n", " 'y': city_populations, \n", " 'text': names_and_ranks, \n", " 'type': 'bar', \n", " 'name': 'populations'}"]}, {"cell_type": "code", "execution_count": null, "metadata": {}, "outputs": [], "source": ["import plotly\n", "plotly.offline.init_notebook_mode(connected=True)\n", "plotly.offline.iplot([trace_populations])"]}, {"cell_type": "markdown", "metadata": {}, "source": ["Now we want declare a variable called `city_areas` that points to a list of all of the areas of the cities. Let's use a `for` loop to iterate through our `cities` and have `city_areas` equal to each area of the city. "]}, {"cell_type": "code", "execution_count": null, "metadata": {}, "outputs": [], "source": ["city_areas = []"]}, {"cell_type": "code", "execution_count": null, "metadata": {}, "outputs": [], "source": ["trace_areas = {'x': names_and_ranks, 'y': city_areas, 'text': names_and_ranks, 'type': 'bar', 'name': 'areas'}"]}, {"cell_type": "code", "execution_count": null, "metadata": {}, "outputs": [], "source": ["import plotly\n", "plotly.offline.init_notebook_mode(connected=True)\n", "plotly.offline.iplot([trace_populations, trace_areas])"]}, {"cell_type": "markdown", "metadata": {}, "source": ["### Summary"]}, {"cell_type": "markdown", "metadata": {}, "source": ["In this section we saw how we can use `for` loops to go through elements of a list and perform the same operation on each. By using `for` loops we were able to reduce the amount of code that we wrote and while also writing more expressive code."]}], "metadata": {"kernelspec": {"display_name": "Python 3", "language": "python", "name": "python3"}, "language_info": {"codemirror_mode": {"name": "ipython", "version": 3}, "file_extension": ".py", "mimetype": "text/x-python", "name": "python", "nbconvert_exporter": "python", "pygments_lexer": "ipython3", "version": "3.6.6"}}, "nbformat": 4, "nbformat_minor": 2} \ No newline at end of file +{ + "cells": [ + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "# Python For loops Lab" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "### Learning Objectives" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "* Understand how for loops can help us reduce repetition\n", + "* Understand the syntax of for loops " + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "### Picking up where we last left off" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "In the last lesson, we worked with some of our travel data. 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" + ] + }, + "metadata": {}, + "output_type": "display_data" + } + ], + "source": [ + "import plotly\n", + "\n", + "plotly.offline.init_notebook_mode(connected=True)\n", + "\n", + "x_values = [cities[0]['City'], cities[1]['City'], cities[2]['City']]\n", + "y_values = [cities[0]['Population'], cities[1]['Population'], cities[2]['Population']]\n", + "trace_first_three_pops = {'x': x_values, 'y': y_values, 'type': 'bar'}\n", + "plotly.offline.iplot([trace_first_three_pops])" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "Of course, as you may have spotted, there is a good amount of repetition in displaying this data. Just take a look at how we retrieved the data for our `x_values` and `y_values`. " + ] + }, + { + "cell_type": "code", + "execution_count": 3, + "metadata": {}, + "outputs": [], + "source": [ + "x_values = [cities[0]['City'], cities[1]['City'], cities[2]['City']]\n", + "y_values = [cities[0]['Population'], cities[1]['Population'], cities[2]['Population']]" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "So in this lesson, we will use our `for` loop to display information about our travel locations with less repetition." + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "### Working with the For Loop" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "Our `cities` list contains information about the top 12 cities by population. For our upcoming iteration tasks, it will be useful to have a list of the numbers 0 through 11. Use what we know about `len` and `range`to generate a list of numbers 0 through 11. Assign this to a variable called `city_indices`." + ] + }, + { + "cell_type": "code", + "execution_count": 4, + "metadata": {}, + "outputs": [ + { + "data": { + "text/plain": [ + "[0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11]" + ] + }, + "execution_count": 4, + "metadata": {}, + "output_type": "execute_result" + } + ], + "source": [ + "city_indices = list(range(0, len(cities)))\n", + "city_indices # [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11]" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "Now we want to create labels for each of the cities. We'll provide a list of the `city_names` for you. " + ] + }, + { + "cell_type": "code", + "execution_count": 5, + "metadata": {}, + "outputs": [], + "source": [ + "city_names = ['Buenos Aires',\n", + " 'Toronto',\n", + " 'Marakesh',\n", + " 'Albuquerque',\n", + " 'Los Cabos',\n", + " 'Greenville',\n", + " 'Archipelago Sea',\n", + " 'Pyeongchang',\n", + " 'Walla Walla Valley',\n", + " 'Salina Island',\n", + " 'Solta',\n", + " 'Iguazu Falls']" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "Your task is to assign the variable `names_and_ranks` to a list, with each element equal to the city name and it's corresponding rank. For example, the first element would be, `\"1. Buenos Aires\"` and the second would be `\"2. Toronto\"`. Use a `for` loop and the lists `city_indices` and `city_names` to accomplish this. We'll need to perform some nifty string interpolation to format our strings properly. Check out [f-string interpolation](https://www.programiz.com/python-programming/string-interpolation#f) to see how we can pass values into a string. Remember that list indices start at zero, but we want our `names_and_ranks` list to start at one!" + ] + }, + { + "cell_type": "code", + "execution_count": 8, + "metadata": {}, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "['1. Buenos Aires', '2. Toronto', '3. Marakesh', '4. Albuquerque', '5. Los Cabos', '6. Greenville', '7. Archipelago Sea', '8. Pyeongchang', '9. Walla Walla Valley', '10. Salina Island', '11. Solta', '12. Iguazu Falls']\n" + ] + } + ], + "source": [ + "names_and_ranks = [] \n", + "for city_index in city_indices:\n", + " rank = city_index + 1\n", + " names_and_ranks.append(f'{rank}. {city_names[city_index]}')\n", + "# write a for loop that adds the properly formatted string to the names_and_ranks list\n", + "print(names_and_ranks)" + ] + }, + { + "cell_type": "code", + "execution_count": 7, + "metadata": {}, + "outputs": [ + { + "data": { + "text/plain": [ + "'12. Iguazu Falls'" + ] + }, + "execution_count": 7, + "metadata": {}, + "output_type": "execute_result" + } + ], + "source": [ + "names_and_ranks[0] # '1. Buenos Aires'\n", + "names_and_ranks[1] # '2. Toronto'\n", + "names_and_ranks[-1] # '12. Iguazu Falls'" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "Ok, now let's create a new variable called `city_populations`. Use a `for` loop to iterate through `cities` and have `city_populations` equal to each of the populations." + ] + }, + { + "cell_type": "code", + "execution_count": 9, + "metadata": {}, + "outputs": [ + { + "data": { + "text/plain": [ + "[2891, 2732, 929, 559, 288, 93, 60, 44, 33, 3, 2, 0]" + ] + }, + "execution_count": 9, + "metadata": {}, + "output_type": "execute_result" + } + ], + "source": [ + "city_populations = []\n", + "for city_index in city_indices:\n", + " city_populations.append(cities[city_index]['Population'])\n", + "city_populations" + ] + }, + { + "cell_type": "code", + "execution_count": 10, + "metadata": {}, + "outputs": [ + { + "data": { + "text/plain": [ + "0" + ] + }, + "execution_count": 10, + "metadata": {}, + "output_type": "execute_result" + } + ], + "source": [ + "city_populations[0] # 2891\n", + "city_populations[1] # 2732\n", + "city_populations[-1] # 0" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "Great! Now we can begin to plot this data. First, let's create a trace of our populations and set it to the variable `trace_populations`." + ] + }, + { + "cell_type": "code", + "execution_count": 11, + "metadata": {}, + "outputs": [], + "source": [ + "trace_populations = {'x': names_and_ranks, \n", + " 'y': city_populations, \n", + " 'text': names_and_ranks, \n", + " 'type': 'bar', \n", + " 'name': 'populations'}" + ] + }, + { + "cell_type": "code", + "execution_count": 12, + "metadata": {}, + "outputs": [ + { + "data": { + "text/html": [ + " \n", + " " + ] + }, + "metadata": {}, + "output_type": "display_data" + }, + { + "data": { + "application/vnd.plotly.v1+json": { + "config": { + "linkText": "Export to plot.ly", + "plotlyServerURL": "https://plot.ly", + "showLink": false + }, + "data": [ + { + "name": "populations", + "text": [ + "1. Buenos Aires", + "2. Toronto", + "3. Marakesh", + "4. Albuquerque", + "5. Los Cabos", + "6. Greenville", + "7. Archipelago Sea", + "8. Pyeongchang", + "9. 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\n", + " \n", + " \n", + "
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" + ] + }, + "metadata": {}, + "output_type": "display_data" + } + ], + "source": [ + "import plotly\n", + "plotly.offline.init_notebook_mode(connected=True)\n", + "plotly.offline.iplot([trace_populations])" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "Now we want declare a variable called `city_areas` that points to a list of all of the areas of the cities. Let's use a `for` loop to iterate through our `cities` and have `city_areas` equal to each area of the city. " + ] + }, + { + "cell_type": "code", + "execution_count": 13, + "metadata": {}, + "outputs": [ + { + "data": { + "text/plain": [ + "[203, 630, 230, 491, 3751, 68, 2000, 1464, 35, 26, 59, 2396]" + ] + }, + "execution_count": 13, + "metadata": {}, + "output_type": "execute_result" + } + ], + "source": [ + "city_areas = []\n", + "for city_index in city_indices:\n", + " city_areas.append(cities[city_index]['Area'])\n", + "city_areas" + ] + }, + { + "cell_type": "code", + "execution_count": 14, + "metadata": {}, + "outputs": [], + "source": [ + "trace_areas = {'x': names_and_ranks, 'y': city_areas, 'text': names_and_ranks, 'type': 'bar', 'name': 'areas'}" + ] + }, + { + "cell_type": "code", + "execution_count": 15, + "metadata": {}, + "outputs": [ + { + "data": { + "text/html": [ + " \n", + " " + ] + }, + "metadata": {}, + "output_type": "display_data" + }, + { + "data": { + "application/vnd.plotly.v1+json": { + "config": { + "linkText": "Export to plot.ly", + "plotlyServerURL": "https://plot.ly", + "showLink": false + }, + "data": [ + { + "name": "populations", + "text": [ + "1. 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" + ] + }, + "metadata": {}, + "output_type": "display_data" + } + ], + "source": [ + "import plotly\n", + "plotly.offline.init_notebook_mode(connected=True)\n", + "plotly.offline.iplot([trace_populations, trace_areas])" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "### Summary" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "In this section we saw how we can use `for` loops to go through elements of a list and perform the same operation on each. By using `for` loops we were able to reduce the amount of code that we wrote and while also writing more expressive code." + ] + } + ], + "metadata": { + "kernelspec": { + "display_name": "Python 3", + "language": "python", + "name": "python3" + }, + "language_info": { + "codemirror_mode": { + "name": "ipython", + "version": 3 + }, + "file_extension": ".py", + "mimetype": "text/x-python", + "name": "python", + "nbconvert_exporter": "python", + "pygments_lexer": "ipython3", + "version": "3.6.9" + } + }, + "nbformat": 4, + "nbformat_minor": 2 +}