diff --git a/index.ipynb b/index.ipynb
index cd283629c8d..ad06e8f2ac9 100644
--- a/index.ipynb
+++ b/index.ipynb
@@ -1 +1,3153 @@
-{"cells": [{"cell_type": "markdown", "metadata": {}, "source": ["# Python For loops Lab"]}, {"cell_type": "markdown", "metadata": {}, "source": ["### Learning Objectives"]}, {"cell_type": "markdown", "metadata": {}, "source": ["* Understand how for loops can help us reduce repetition\n", "* Understand the syntax of for loops "]}, {"cell_type": "markdown", "metadata": {}, "source": ["### Picking up where we last left off"]}, {"cell_type": "markdown", "metadata": {}, "source": ["In the last lesson, we worked with some of our travel data. Let's retrieve a list with our travel information again from excel. First, we read the information from excel as a list of dictionaries, with each dictionary representing a location. And we assign this list to the variable `cities`."]}, {"cell_type": "code", "execution_count": null, "metadata": {}, "outputs": [], "source": ["import pandas\n", "file_name = './cities.xlsx'\n", "travel_df = pandas.read_excel(file_name)\n", "cities = travel_df.to_dict('records')"]}, {"cell_type": "markdown", "metadata": {}, "source": ["Next, we retrieve the first three city names, stored as the `'City'` attribute of each dictionary, and `'Population'` of each of the cities. Then we plot the names as our `x_values` and the populations as our `y_values`."]}, {"cell_type": "code", "execution_count": null, "metadata": {}, "outputs": [], "source": ["import plotly\n", "\n", "plotly.offline.init_notebook_mode(connected=True)\n", "\n", "x_values = [cities[0]['City'], cities[1]['City'], cities[2]['City']]\n", "y_values = [cities[0]['Population'], cities[1]['Population'], cities[2]['Population']]\n", "trace_first_three_pops = {'x': x_values, 'y': y_values, 'type': 'bar'}\n", "plotly.offline.iplot([trace_first_three_pops])"]}, {"cell_type": "markdown", "metadata": {}, "source": ["Of course, as you may have spotted, there is a good amount of repetition in displaying this data. Just take a look at how we retrieved the data for our `x_values` and `y_values`. "]}, {"cell_type": "code", "execution_count": null, "metadata": {}, "outputs": [], "source": ["x_values = [cities[0]['City'], cities[1]['City'], cities[2]['City']]\n", "y_values = [cities[0]['Population'], cities[1]['Population'], cities[2]['Population']]"]}, {"cell_type": "markdown", "metadata": {}, "source": ["So in this lesson, we will use our `for` loop to display information about our travel locations with less repetition."]}, {"cell_type": "markdown", "metadata": {}, "source": ["### Working with the For Loop"]}, {"cell_type": "markdown", "metadata": {}, "source": ["Our `cities` list contains information about the top 12 cities by population. For our upcoming iteration tasks, it will be useful to have a list of the numbers 0 through 11. Use what we know about `len` and `range`to generate a list of numbers 0 through 11. Assign this to a variable called `city_indices`."]}, {"cell_type": "code", "execution_count": null, "metadata": {}, "outputs": [], "source": ["city_indices = None\n", "city_indices # [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11]"]}, {"cell_type": "markdown", "metadata": {}, "source": ["Now we want to create labels for each of the cities. We'll provide a list of the `city_names` for you. "]}, {"cell_type": "code", "execution_count": null, "metadata": {}, "outputs": [], "source": ["city_names = ['Buenos Aires',\n", " 'Toronto',\n", " 'Marakesh',\n", " 'Albuquerque',\n", " 'Los Cabos',\n", " 'Greenville',\n", " 'Archipelago Sea',\n", " 'Pyeongchang',\n", " 'Walla Walla Valley',\n", " 'Salina Island',\n", " 'Solta',\n", " 'Iguazu Falls']"]}, {"cell_type": "markdown", "metadata": {}, "source": ["Your task is to assign the variable `names_and_ranks` to a list, with each element equal to the city name and it's corresponding rank. For example, the first element would be, `\"1. Buenos Aires\"` and the second would be `\"2. Toronto\"`. Use a `for` loop and the lists `city_indices` and `city_names` to accomplish this. We'll need to perform some nifty string interpolation to format our strings properly. Check out [f-string interpolation](https://www.programiz.com/python-programming/string-interpolation#f) to see how we can pass values into a string. Remember that list indices start at zero, but we want our `names_and_ranks` list to start at one!"]}, {"cell_type": "code", "execution_count": null, "metadata": {}, "outputs": [], "source": ["names_and_ranks = [] \n", "# write a for loop that adds the properly formatted string to the names_and_ranks list"]}, {"cell_type": "code", "execution_count": null, "metadata": {}, "outputs": [], "source": ["names_and_ranks[0] # '1. Buenos Aires'\n", "names_and_ranks[1] # '2. Toronto'\n", "names_and_ranks[-1] # '12. Iguazu Falls'"]}, {"cell_type": "markdown", "metadata": {}, "source": ["Ok, now let's create a new variable called `city_populations`. Use a `for` loop to iterate through `cities` and have `city_populations` equal to each of the populations."]}, {"cell_type": "code", "execution_count": null, "metadata": {}, "outputs": [], "source": ["city_populations = []"]}, {"cell_type": "code", "execution_count": null, "metadata": {}, "outputs": [], "source": ["city_populations[0] # 2891\n", "city_populations[1] # 2732\n", "city_populations[-1] # 0"]}, {"cell_type": "markdown", "metadata": {}, "source": ["Great! Now we can begin to plot this data. First, let's create a trace of our populations and set it to the variable `trace_populations`."]}, {"cell_type": "code", "execution_count": null, "metadata": {}, "outputs": [], "source": ["trace_populations = {'x': names_and_ranks, \n", " 'y': city_populations, \n", " 'text': names_and_ranks, \n", " 'type': 'bar', \n", " 'name': 'populations'}"]}, {"cell_type": "code", "execution_count": null, "metadata": {}, "outputs": [], "source": ["import plotly\n", "plotly.offline.init_notebook_mode(connected=True)\n", "plotly.offline.iplot([trace_populations])"]}, {"cell_type": "markdown", "metadata": {}, "source": ["Now we want declare a variable called `city_areas` that points to a list of all of the areas of the cities. Let's use a `for` loop to iterate through our `cities` and have `city_areas` equal to each area of the city. "]}, {"cell_type": "code", "execution_count": null, "metadata": {}, "outputs": [], "source": ["city_areas = []"]}, {"cell_type": "code", "execution_count": null, "metadata": {}, "outputs": [], "source": ["trace_areas = {'x': names_and_ranks, 'y': city_areas, 'text': names_and_ranks, 'type': 'bar', 'name': 'areas'}"]}, {"cell_type": "code", "execution_count": null, "metadata": {}, "outputs": [], "source": ["import plotly\n", "plotly.offline.init_notebook_mode(connected=True)\n", "plotly.offline.iplot([trace_populations, trace_areas])"]}, {"cell_type": "markdown", "metadata": {}, "source": ["### Summary"]}, {"cell_type": "markdown", "metadata": {}, "source": ["In this section we saw how we can use `for` loops to go through elements of a list and perform the same operation on each. By using `for` loops we were able to reduce the amount of code that we wrote and while also writing more expressive code."]}], "metadata": {"kernelspec": {"display_name": "Python 3", "language": "python", "name": "python3"}, "language_info": {"codemirror_mode": {"name": "ipython", "version": 3}, "file_extension": ".py", "mimetype": "text/x-python", "name": "python", "nbconvert_exporter": "python", "pygments_lexer": "ipython3", "version": "3.6.6"}}, "nbformat": 4, "nbformat_minor": 2}
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\n",
+ " \n",
+ " \n",
+ "
\n",
+ " \n",
+ "
"
+ ]
+ },
+ "metadata": {},
+ "output_type": "display_data"
+ }
+ ],
+ "source": [
+ "import plotly\n",
+ "\n",
+ "plotly.offline.init_notebook_mode(connected=True)\n",
+ "\n",
+ "x_values = [cities[0]['City'], cities[1]['City'], cities[2]['City']]\n",
+ "y_values = [cities[0]['Population'], cities[1]['Population'], cities[2]['Population']]\n",
+ "trace_first_three_pops = {'x': x_values, 'y': y_values, 'type': 'bar'}\n",
+ "plotly.offline.iplot([trace_first_three_pops])"
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "Of course, as you may have spotted, there is a good amount of repetition in displaying this data. Just take a look at how we retrieved the data for our `x_values` and `y_values`. "
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 3,
+ "metadata": {},
+ "outputs": [],
+ "source": [
+ "x_values = [cities[0]['City'], cities[1]['City'], cities[2]['City']]\n",
+ "y_values = [cities[0]['Population'], cities[1]['Population'], cities[2]['Population']]"
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "So in this lesson, we will use our `for` loop to display information about our travel locations with less repetition."
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "### Working with the For Loop"
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "Our `cities` list contains information about the top 12 cities by population. For our upcoming iteration tasks, it will be useful to have a list of the numbers 0 through 11. Use what we know about `len` and `range`to generate a list of numbers 0 through 11. Assign this to a variable called `city_indices`."
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 4,
+ "metadata": {},
+ "outputs": [
+ {
+ "data": {
+ "text/plain": [
+ "[0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11]"
+ ]
+ },
+ "execution_count": 4,
+ "metadata": {},
+ "output_type": "execute_result"
+ }
+ ],
+ "source": [
+ "city_indices = list(range(0, len(cities)))\n",
+ "city_indices # [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11]"
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "Now we want to create labels for each of the cities. We'll provide a list of the `city_names` for you. "
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 5,
+ "metadata": {},
+ "outputs": [],
+ "source": [
+ "city_names = ['Buenos Aires',\n",
+ " 'Toronto',\n",
+ " 'Marakesh',\n",
+ " 'Albuquerque',\n",
+ " 'Los Cabos',\n",
+ " 'Greenville',\n",
+ " 'Archipelago Sea',\n",
+ " 'Pyeongchang',\n",
+ " 'Walla Walla Valley',\n",
+ " 'Salina Island',\n",
+ " 'Solta',\n",
+ " 'Iguazu Falls']"
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "Your task is to assign the variable `names_and_ranks` to a list, with each element equal to the city name and it's corresponding rank. For example, the first element would be, `\"1. Buenos Aires\"` and the second would be `\"2. Toronto\"`. Use a `for` loop and the lists `city_indices` and `city_names` to accomplish this. We'll need to perform some nifty string interpolation to format our strings properly. Check out [f-string interpolation](https://www.programiz.com/python-programming/string-interpolation#f) to see how we can pass values into a string. Remember that list indices start at zero, but we want our `names_and_ranks` list to start at one!"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 8,
+ "metadata": {},
+ "outputs": [
+ {
+ "name": "stdout",
+ "output_type": "stream",
+ "text": [
+ "['1. Buenos Aires', '2. Toronto', '3. Marakesh', '4. Albuquerque', '5. Los Cabos', '6. Greenville', '7. Archipelago Sea', '8. Pyeongchang', '9. Walla Walla Valley', '10. Salina Island', '11. Solta', '12. Iguazu Falls']\n"
+ ]
+ }
+ ],
+ "source": [
+ "names_and_ranks = [] \n",
+ "for city_index in city_indices:\n",
+ " rank = city_index + 1\n",
+ " names_and_ranks.append(f'{rank}. {city_names[city_index]}')\n",
+ "# write a for loop that adds the properly formatted string to the names_and_ranks list\n",
+ "print(names_and_ranks)"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 7,
+ "metadata": {},
+ "outputs": [
+ {
+ "data": {
+ "text/plain": [
+ "'12. Iguazu Falls'"
+ ]
+ },
+ "execution_count": 7,
+ "metadata": {},
+ "output_type": "execute_result"
+ }
+ ],
+ "source": [
+ "names_and_ranks[0] # '1. Buenos Aires'\n",
+ "names_and_ranks[1] # '2. Toronto'\n",
+ "names_and_ranks[-1] # '12. Iguazu Falls'"
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "Ok, now let's create a new variable called `city_populations`. Use a `for` loop to iterate through `cities` and have `city_populations` equal to each of the populations."
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 9,
+ "metadata": {},
+ "outputs": [
+ {
+ "data": {
+ "text/plain": [
+ "[2891, 2732, 929, 559, 288, 93, 60, 44, 33, 3, 2, 0]"
+ ]
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+ "execution_count": 9,
+ "metadata": {},
+ "output_type": "execute_result"
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+ "source": [
+ "city_populations = []\n",
+ "for city_index in city_indices:\n",
+ " city_populations.append(cities[city_index]['Population'])\n",
+ "city_populations"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 10,
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+ "0"
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+ "execution_count": 10,
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+ "source": [
+ "city_populations[0] # 2891\n",
+ "city_populations[1] # 2732\n",
+ "city_populations[-1] # 0"
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "Great! Now we can begin to plot this data. First, let's create a trace of our populations and set it to the variable `trace_populations`."
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 11,
+ "metadata": {},
+ "outputs": [],
+ "source": [
+ "trace_populations = {'x': names_and_ranks, \n",
+ " 'y': city_populations, \n",
+ " 'text': names_and_ranks, \n",
+ " 'type': 'bar', \n",
+ " 'name': 'populations'}"
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+ " \n",
+ "
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+ ]
+ },
+ "metadata": {},
+ "output_type": "display_data"
+ }
+ ],
+ "source": [
+ "import plotly\n",
+ "plotly.offline.init_notebook_mode(connected=True)\n",
+ "plotly.offline.iplot([trace_populations])"
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "Now we want declare a variable called `city_areas` that points to a list of all of the areas of the cities. Let's use a `for` loop to iterate through our `cities` and have `city_areas` equal to each area of the city. "
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 13,
+ "metadata": {},
+ "outputs": [
+ {
+ "data": {
+ "text/plain": [
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+ ]
+ },
+ "execution_count": 13,
+ "metadata": {},
+ "output_type": "execute_result"
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+ ],
+ "source": [
+ "city_areas = []\n",
+ "for city_index in city_indices:\n",
+ " city_areas.append(cities[city_index]['Area'])\n",
+ "city_areas"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 14,
+ "metadata": {},
+ "outputs": [],
+ "source": [
+ "trace_areas = {'x': names_and_ranks, 'y': city_areas, 'text': names_and_ranks, 'type': 'bar', 'name': 'areas'}"
+ ]
+ },
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+ "source": [
+ "import plotly\n",
+ "plotly.offline.init_notebook_mode(connected=True)\n",
+ "plotly.offline.iplot([trace_populations, trace_areas])"
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
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+ "### Summary"
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "In this section we saw how we can use `for` loops to go through elements of a list and perform the same operation on each. By using `for` loops we were able to reduce the amount of code that we wrote and while also writing more expressive code."
+ ]
+ }
+ ],
+ "metadata": {
+ "kernelspec": {
+ "display_name": "Python 3",
+ "language": "python",
+ "name": "python3"
+ },
+ "language_info": {
+ "codemirror_mode": {
+ "name": "ipython",
+ "version": 3
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+ "mimetype": "text/x-python",
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