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Author: jimit105

2107-find-unique-binary-string/README.md

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+<p>Given an array of strings <code>nums</code> containing <code>n</code> <strong>unique</strong> binary strings each of length <code>n</code>, return <em>a binary string of length </em><code>n</code><em> that <strong>does not appear</strong> in </em><code>nums</code><em>. If there are multiple answers, you may return <strong>any</strong> of them</em>.</p>
+
+<p>&nbsp;</p>
+<p><strong class="example">Example 1:</strong></p>
+
+<pre>
+<strong>Input:</strong> nums = [&quot;01&quot;,&quot;10&quot;]
+<strong>Output:</strong> &quot;11&quot;
+<strong>Explanation:</strong> &quot;11&quot; does not appear in nums. &quot;00&quot; would also be correct.
+</pre>
+
+<p><strong class="example">Example 2:</strong></p>
+
+<pre>
+<strong>Input:</strong> nums = [&quot;00&quot;,&quot;01&quot;]
+<strong>Output:</strong> &quot;11&quot;
+<strong>Explanation:</strong> &quot;11&quot; does not appear in nums. &quot;10&quot; would also be correct.
+</pre>
+
+<p><strong class="example">Example 3:</strong></p>
+
+<pre>
+<strong>Input:</strong> nums = [&quot;111&quot;,&quot;011&quot;,&quot;001&quot;]
+<strong>Output:</strong> &quot;101&quot;
+<strong>Explanation:</strong> &quot;101&quot; does not appear in nums. &quot;000&quot;, &quot;010&quot;, &quot;100&quot;, and &quot;110&quot; would also be correct.
+</pre>
+
+<p>&nbsp;</p>
+<p><strong>Constraints:</strong></p>
+
+<ul>
+	<li><code>n == nums.length</code></li>
+	<li><code>1 &lt;= n &lt;= 16</code></li>
+	<li><code>nums[i].length == n</code></li>
+	<li><code>nums[i] </code>is either <code>&#39;0&#39;</code> or <code>&#39;1&#39;</code>.</li>
+	<li>All the strings of <code>nums</code> are <strong>unique</strong>.</li>
+</ul>

2107-find-unique-binary-string/solution.py

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+# Approach 4: Cantor's Diagonal Argument
+
+# Time: O(n)
+# Space: O(1)
+
+class Solution:
+    def findDifferentBinaryString(self, nums: List[str]) -> str:
+        ans = []
+
+        for i in range(len(nums)):
+            curr = nums[i][i]
+            ans.append('1' if curr == '0' else '0')
+
+        return ''.join(ans)
+