Sync LeetCode submission Runtime - 3 ms (23.22%), Memory - 18 MB (12.54%)

Author: jimit105

3429-special-array-i/README.md

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+<p>An array is considered <strong>special</strong> if every pair of its adjacent elements contains two numbers with different parity.<!-- notionvc: e6bed0fa-c67d-43a7-81b4-99fb85b99e98 --></p>
+
+<p>You are given an array of integers <code>nums</code>. Return <code>true</code> if <code>nums</code> is a <strong>special</strong> array, otherwise, return <code>false</code>.</p>
+
+<p>&nbsp;</p>
+<p><strong class="example">Example 1:</strong></p>
+
+<div class="example-block">
+<p><strong>Input:</strong> <span class="example-io">nums = [1]</span></p>
+
+<p><strong>Output:</strong> <span class="example-io">true</span></p>
+
+<p><strong>Explanation:</strong></p>
+
+<p>There is only one element. So the answer is <code>true</code>.</p>
+</div>
+
+<p><strong class="example">Example 2:</strong></p>
+
+<div class="example-block">
+<p><strong>Input:</strong> <span class="example-io">nums = [2,1,4]</span></p>
+
+<p><strong>Output:</strong> <span class="example-io">true</span></p>
+
+<p><strong>Explanation:</strong></p>
+
+<p>There is only two pairs: <code>(2,1)</code> and <code>(1,4)</code>, and both of them contain numbers with different parity. So the answer is <code>true</code>.</p>
+</div>
+
+<p><strong class="example">Example 3:</strong></p>
+
+<div class="example-block">
+<p><strong>Input:</strong> <span class="example-io">nums = [4,3,1,6]</span></p>
+
+<p><strong>Output:</strong> <span class="example-io">false</span></p>
+
+<p><strong>Explanation:</strong></p>
+
+<p><code>nums[1]</code> and <code>nums[2]</code> are both odd. So the answer is <code>false</code>.</p>
+</div>
+
+<p>&nbsp;</p>
+<p><strong>Constraints:</strong></p>
+
+<ul>
+	<li><code>1 &lt;= nums.length &lt;= 100</code></li>
+	<li><code>1 &lt;= nums[i] &lt;= 100</code></li>
+</ul>

3429-special-array-i/solution.py

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+# Approach: Linear Scan
+
+# Time: O(n)
+# Space: O(1)
+
+class Solution:
+    def isArraySpecial(self, nums: List[int]) -> bool:
+        for i in range(len(nums) - 1):
+            if (nums[i] % 2) == (nums[i + 1] % 2):
+                return False
+        
+        return True
+