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Author: jimit105

3321-type-of-triangle/README.md

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+<p>You are given a <strong>0-indexed</strong> integer array <code>nums</code> of size <code>3</code> which can form the sides of a triangle.</p>
+
+<ul>
+	<li>A triangle is called <strong>equilateral</strong> if it has all sides of equal length.</li>
+	<li>A triangle is called <strong>isosceles</strong> if it has exactly two sides of equal length.</li>
+	<li>A triangle is called <strong>scalene</strong> if all its sides are of different lengths.</li>
+</ul>
+
+<p>Return <em>a string representing</em> <em>the type of triangle that can be formed </em><em>or </em><code>&quot;none&quot;</code><em> if it <strong>cannot</strong> form a triangle.</em></p>
+
+<p>&nbsp;</p>
+<p><strong class="example">Example 1:</strong></p>
+
+<pre>
+<strong>Input:</strong> nums = [3,3,3]
+<strong>Output:</strong> &quot;equilateral&quot;
+<strong>Explanation:</strong> Since all the sides are of equal length, therefore, it will form an equilateral triangle.
+</pre>
+
+<p><strong class="example">Example 2:</strong></p>
+
+<pre>
+<strong>Input:</strong> nums = [3,4,5]
+<strong>Output:</strong> &quot;scalene&quot;
+<strong>Explanation:</strong> 
+nums[0] + nums[1] = 3 + 4 = 7, which is greater than nums[2] = 5.
+nums[0] + nums[2] = 3 + 5 = 8, which is greater than nums[1] = 4.
+nums[1] + nums[2] = 4 + 5 = 9, which is greater than nums[0] = 3. 
+Since the sum of the two sides is greater than the third side for all three cases, therefore, it can form a triangle.
+As all the sides are of different lengths, it will form a scalene triangle.
+</pre>
+
+<p>&nbsp;</p>
+<p><strong>Constraints:</strong></p>
+
+<ul>
+	<li><code>nums.length == 3</code></li>
+	<li><code>1 &lt;= nums[i] &lt;= 100</code></li>
+</ul>

3321-type-of-triangle/solution.py

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+# Approach: Math
+
+class Solution:
+    def triangleType(self, nums: List[int]) -> str:
+        nums.sort()
+        if nums[0] + nums[1] <= nums[2]:
+            return "none"
+        elif nums[0] == nums[2]:
+            return "equilateral"
+        elif nums[0] == nums[1] or nums[1] == nums[2]:
+            return "isosceles"
+        else:
+            return "scalene"
+