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One of the more common cases of allocation size calculations is finding
the size of a structure that has a zero-sized array at the end, along
with memory for some number of elements for that array. For example:
struct dlm_migratable_lockres
{
...
struct dlm_migratable_lock ml[0]; // 16 bytes each, begins at byte 112
};
Make use of the struct_size() helper instead of an open-coded version in
order to avoid any potential type mistakes.
So, replace the following form:
sizeof(struct dlm_migratable_lockres) + (mres->num_locks * sizeof(struct dlm_migratable_lock))
with:
struct_size(mres, ml, mres->num_locks)
Notice that, in this case, variable sz is not necessary, hence it is
removed.
This code was detected with the help of Coccinelle.
Link: http://lkml.kernel.org/r/20190605204926.GA24467@embeddedor
Signed-off-by: Gustavo A. R. Silva <[email protected]>
Reviewed-by: Joseph Qi <[email protected]>
Cc: Mark Fasheh <[email protected]>
Cc: Joel Becker <[email protected]>
Cc: Junxiao Bi <[email protected]>
Cc: Changwei Ge <[email protected]>
Cc: Gang He <[email protected]>
Cc: Jun Piao <[email protected]>
Signed-off-by: Andrew Morton <[email protected]>
Signed-off-by: Linus Torvalds <[email protected]>
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