x86/umip: Check that the instruction opcode is at least two bytes

When checking for a potential UMIP violation on #GP, verify the decoder found
at least two opcode bytes to avoid false positives when the kernel encounters
an unknown instruction that starts with 0f.  Because the array of opcode.bytes
is zero-initialized by insn_init(), peeking at bytes[1] will misinterpret
garbage as a potential SLDT or STR instruction, and can incorrectly trigger
emulation.

E.g. if a VPALIGNR instruction

   62 83 c5 05 0f 08 ff     vpalignr xmm17{k5},xmm23,XMMWORD PTR [r8],0xff

hits a #GP, the kernel emulates it as STR and squashes the #GP (and corrupts
the userspace code stream).

Arguably the check should look for exactly two bytes, but no three byte
opcodes use '0f 00 xx' or '0f 01 xx' as an escape, i.e. it should be
impossible to get a false positive if the first two opcode bytes match '0f 00'
or '0f 01'.  Go with a more conservative check with respect to the existing
code to minimize the chances of breaking userspace, e.g. due to decoder
weirdness.

Analyzed by Nick Bray <[email protected]>.

Fixes: 1e5db22 ("x86/umip: Add emulation code for UMIP instructions")
Reported-by: Dan Snyder <[email protected]>
Signed-off-by: Sean Christopherson <[email protected]>
Signed-off-by: Borislav Petkov (AMD) <[email protected]>
Acked-by: Peter Zijlstra (Intel) <[email protected]>
Cc: [email protected]

Author: sean-jc

arch/x86/kernel/umip.c

@@ -156,8 +156,8 @@ static int identify_insn(struct insn *insn)
 	if (!insn->modrm.nbytes)
 		return -EINVAL;
 
-	/* All the instructions of interest start with 0x0f. */
-	if (insn->opcode.bytes[0] != 0xf)
+	/* The instructions of interest have 2-byte opcodes: 0F 00 or 0F 01. */
+	if (insn->opcode.nbytes < 2 || insn->opcode.bytes[0] != 0xf)
 		return -EINVAL;
 
 	if (insn->opcode.bytes[1] == 0x1) {